A person claps his hands near a cliff and hears the echo after 5s. What is the distance or the cliff from the person if the speed of the sound is taken as 330ms–1?
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Answered by
3
find out from this.
d = (v×t) ÷ 2..........eq 1
because sound will be listened after covering double distance so we need to half the distance as in eq 1..
d = (330×5) ÷2
d = 825 approximately
.
.
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d = (v×t) ÷ 2..........eq 1
because sound will be listened after covering double distance so we need to half the distance as in eq 1..
d = (330×5) ÷2
d = 825 approximately
.
.
mark this answer as brainliest and follow me too
javedsaif0:
please mark this answer as brainliest and follow me too
Answered by
0
Answer:
Distance=speedxtime
S=330x5
S=1650mts
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