Question

a person climbs 12 mix 2 by 3 metre above the water to the top of a cliff he dives into the water and reaches -3 makes 1 by 6 metre below the surface what is the difference in these height​

Answer 1

Answer:

$15\frac{5}{6} m$

Step-by-step explanation:

a person climbs 12 2/3  metre above the water to the top of a cliff he dives into the water and reaches -3  1/ 6 metre below the surface what is the difference in these height​

Above height = 12 2/3  = 38/3

Below height = - 3 1/6 = -19/6

Difference in hegihts =  38/3  - (-19/6)

= 38/3  + 19/6

= 76/6 + 19/6

= 95/6

difference in these height​ = 95/6 m = 15 5/6 m

Answer 2

Answer:

Step-by-step explanation:

Person when he climbs above the height = 12 mix 2/3  = 38/3 (Given)

Person when he goes below the height = - 3 mix 1/6 = -19/6 (Given)

Speed, s = Distance (d)/ Time (t) which means that the speed equals distance divided by the time. However, we need to calculate the height, thus -

Thus, the difference in the height =  38/3  - (-19/6)

= 38/3  + 19/6

= 76/6 + 19/6

= 95/6

Therefore, the overall difference between these heights = 95/6 m