Question

A person climbs up and another person climb down a rope hanging from a tree with uniform acceleration separately. If the respective masses of person are in the ratio 3:5 the common acceleration must be​

Answer 1

3;er2(er+2983859184928493

Answer 2

Acceleration :

Explanation:

• The acceleration is the rate of change of the velocity of an object with respect to time.

• Acceleration is a vector quantity.

• Gravity is the force by which earth attracts all bodies towards itself. It is the same for all bodies and does not depend upon the mass of the body.

 Let T be the tension in the rope.

When a person climbs up with acceleration a, is given by

$\displaystyle T - m_1\ g = m_1\ a$

When another monkey climbs down with the same acceleration a, is given by

$\displaystyle m_2\ g - Tm_2\ a$

adding above eq, we get

$\displaystyle a=\frac{(m2-m1)g/(m2+m1)}{(m2+m1)}$

$\displaystyle a = \frac{(3-2)g}{3+2}$

$\displaystyle \mathbf{a = \frac{g}{5} }$