A person covers a certain distance at a certain speed if he decreases his speed by 20% then he takes 16 minutes more to cover the same distance find the taken by him to cover the distance at original speed
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Answer: 64 min
Explanation:
1) Original Speed =S1 =x ; Original time = T1 =T
2) Speed decreased by 20% hence time taken is 16 min more than original time
: S2= x-x/4= (4/5)x ; T2 =T+16
Now Distance is constant
Hence, Speed is inversely proportional to time
Therefore:
T1/T2 =S2/S1
= (4/5)x/ x
=4/5
Difference in th ratio of time is 1 unit (5-4)
which is equal to 16 min [T-(T+16)]
■ 1 unit >>>>> 16 min
Now multiply this 1 unit with the time ratio
T1/T2 = 4×1 unit/5×1 unit
T1/T2 = 4× 16 min/ 5×16 min
T1/T2 = 64 min / 80 min
Hence ,Original speed = T1 = T = 64 min
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