Question

A Person crossing a road with a certain
velocity due north, sees a car moving
towards east. The relative velocity of the car
w.rct the person is 2. times that of the ve-
locity of the person. The angle made by the
relative velocity with the east is
1.1) 30° 2) 45° 3) 60° 4) 90°​

Answer 1

Answer:

60°

EXPLANATION

velocity of person =Vp

velocity of car = Vc

relative velocity =Vcp

Vcp=Vc-Vp...(1)

given

Vcp=2Vp

sub in (1)

2Vp=Vc-Vp

3Vp=Vc...{2}

angle made by relative celocity speed is

tan Φ=Vc/Vp

tanΦ=3Vp/Vp

tan Φ= 3

Φ = 60°

Answer 2

Explanation:

ans is 45 ..vc-vp ..so the ans is 45 degrees