Question

a person crossing the road with a certain velocity due north , sees a car moving towards east . relative velocity of the car with respect to the person is √2 times that of velocity of the person . the angle made by the relative velocity with the cast is​

Answer 1

Answer:

hmm

Explanation:

Answer: Sorry but I don't know

Answer 2

$\qquad \sf\overrightarrow V_{cp} = \overrightarrow V_{c} - \overrightarrow V_{p}$

$\qquad \sf\overrightarrow V_{cp} = \sqrt{2} p$

$\displaystyle\qquad \sf \sin \theta = \frac{ \cancel{V_{p}}}{ \sqrt{2} \: \cancel{V_{p}} }$

$\displaystyle\qquad \sf \sin \theta = \frac{1}{ \sqrt{2}}$

$\displaystyle\qquad \sf \sin \theta = 45 \degree$

Hence,

$\displaystyle\qquad \sf \implies \boxed{ \bf \: \theta = 45 \degree}$

$\:$