a person deposit rupees 1000 in the first month. then every month he increases the monthly deposits by Rs.60. calculate his total investment at the end of 2 years
Answers
Answer:
₹3200
Step-by-step explanation:
Money in 1st month = ₹1000
Money in 2nd month = ₹1000+60
= ₹1060
Money in 3rd month = ₹1060+60
= ₹1120
Money in 4th month = ₹1120+60
= ₹1180
Money in 5th month = ₹1180+60
= ₹1240
Money in 6th month = ₹1240+60
= ₹1300
Money in 7th month = ₹1300+60
= ₹1360
Money in 8th month = ₹1360+60
= ₹1420
Money in 9th month = ₹1420+60
= ₹1480
Money in 10th month = ₹1480+60
= ₹1540
Money in 11th month = ₹1540+60
= ₹1600
Money in 12th month = ₹1600+60
= ₹1660
So, money deposited in 1 year = ₹1660
Money deposited in 2 years = ₹1660*2
= ₹3200