A person deposited Rs. 4000 in a bank at 6% compounded continuously, after 3
years the rate of interest was increased to 7% and after 5 more years, the rate was
further increased to 8%, the money was withdrawn at the end of 10 years. Find
the amount
Answers
He will received the amount 1973.88 after 12 years.
Step-by-step explanation:
A person deposited 1000 Rs. in a bank.
He got rate of interest for first 5 years 5%.
A=P(1+R/N)nt
A = future amount
P = Principal amount = 1000 Rs.
r = Rate of interest = 5% = 0.05
n = number of compounding = 1
t = time = 5 years
A=1000(1+R/N)nt
=1000(1+0.05)^5
1000 × (1.05)⁵
= 1000 × 1.276281
= 1276.28 Rs.
Now principal amount would be = 1276.28 Rs.
r = 6% = 0.06
t = 4 years
A=1276.28(1+0.06/1)^4
1276.28(1+0.06)^4
= 1276.28 × 1.26247
= 1611.27 Rs.
The money was withdrawn at the end of 12 years.
The remaining years of deposit = 12 -(5+4) = 3 years
Now principal amount would be = 1611.27 Rs.
r = 7% = 0.07
t = 3 years
A=1611.27(1+0.07/1)(1*3) (* MEANS MULTIPLICATION)
=1611.27(1+0.07)^3
= 1611.27 × 1.2250
= 1973.8750 ≈ 1973.88 Rs.
He will received 1973.88 Rs. at the end of 12 years.