a person deposits Rs 1000 in the first month then every month he increase monthly deposit by Rs 60 calculate his total investment at the end of 2 years ( ans : 40,560 )
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here tge series is 1000,1060,1120,.....24 times
so here a = 1000
deposite = 60
& n =24
then total investment is,
Sn =n/2(2a+(n-1) d)
=24/2 (2*1000+(24-1) 60)
=12(2000+1380)
=3380*12
=40,560 ans
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