A person deposits rs. 500 in a bank , at the beginning of the 1st year, rs. 530 at the beginning of the 2nd year and rs. 520 at the beginning of the 3rd year. the bank pays 8% per annum simple interest. what will be the amount in his account at the end of the 3rd year ?
Answers
Answer:
Step-by-step explanation:
Year 1:
Principal = Rs 500
Interest = 8% of Rs 500
= Rs 40
Year 2:
Principal = Rs 500 + Rs 530
= Rs 1030
Interest = 8% of Rs 1030
= Rs 82.40
Year 3:
Principal = Rs 1030 + Rs 520
= Rs 1550
Interest = Rs 124
Accumulated interest at the end of 3 years = Rs 40 + Rs 82.40 + Rs 124
= Rs 256.40
Total amount in the account at the end 3rd year = Rs 1550 + Rs 256.40
= Rs 1796.40
Answer:
Step-by-step explanation:
Multiples of 2: 2;4;...........100
Multiples of 5: 5;10..........100
In the above series some numbers are repeated twice these are multiples of 10 i.e LCM of 2 and 5
Sum of integers which are divisible by 2 and 5 from 1 to 100=
(Sum of integers which are divisible by 2 from 1 to 100) + (sum of integers which are divisible by 5 from 1 to 100) -(sum of integers which are divisible by 10 from 1 to 100) =
(2+4+......... +100) +(5+10+...... +100) -(10+20+...... 100)
=2(1+2+3+....... 50) + 5(1+2+3+.......20) -10(1+2+3+..... +10) =
2(50(50+1)) ÷2 + 5(20(20+1)) ÷2 -10(10(10+1)) ÷2
=(50(51)) +5(10(20+1) -5(10(11) =
50(51) +5(10(21)-5(10(11) =
2550+1050-550=
3600-550
=3050
Therefore sum of integers from 1 to 100 which are divisible by 2 or 5 is 3050