Math, asked by ketty5566, 4 months ago

A person divided * 2523 into two parts and deposited
them in the name of A and B of his two sons for 3 and
5 yr at compound interest respectively. If both got
same amount, then the amount deposited in the
name of A was?

Answers

Answered by Sahilnokhwal
0

Answer:

Let  A's share be = Rs. x

Then, B's share = Rs. 69,300−x

For A,

N=24−21=3 years 

P= Rs. x, R=10%

On interest being compounded, 

Amount =P(1+100R)N

=x×(1+10010)3

=x×(1.1)3   ....(1)

For B,

N=24−22=2 years

P= Rs. 69,300−x, R=10% 

On interest being compounded, 

Amount =P(1+100R)N

=(69,300−x)×(1+10010)2

=(69,300−x)×(1.1)2 ....(2) 

Given, eqn 1= eqn 2

⇒x×(1.1)3=(69,300−x)×(1.1)2

⇒x×1.1=69,

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