Question

A person does work equal to 2500j in climbing a tree of height 5m. What is the mad of the person? Value of g = 9.8m/s^2 ?

Answer 1

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Given :-

W = 2500j

h = 5 m

g = 9.8 m/s²

★Now :-

${\boxed{\sf\:{Assume\;the\;mass\;of\;person\;be\;m}}}$

★Hence :-

W = m × g × h

2500j = m × 9.8 m/s² × 5m

$\tt{\rightarrow m=\dfrac{2500j}{9.8m/s^2\times 5m}}$

$\tt{\rightarrow\dfrac{2500Nm}{9.8m/s^2\times 5m}}$

$\tt{\rightarrow\dfrac{2500kgm/s^2\times m}{9.8\times 5m^2/s^2}}$

★As we know that (1N = 1kg m/s²)

$\tt{\rightarrow m=\dfrac{2500}{5\times 9.8}kg}$

= 51 kg

$\boxed{\begin{minipage}{11 cm} \textbf{Additional Information} \\ \\ \ Force=Mass\times Acceleration \\ \\ Kinetic Energy = \dfrac{1}{2}\times Mass\times (Velocity)^{2} \\ \\ Potential\; Energy=Mass\times Acceleration\;due\;to\;gravity\times Height \\ \\ Power = \dfrac{Total\;Work\;done}{Time}=\dfrac{Energy}{Time} \end{minipage}}$

Answer 2

Answer:

Given, Work done, W = 2500 J

Height of tree, h = 5 m

We know that, Potential Energy = Work done

So, Potential energy = mgh

Work done = mgh

W = m× 9.8 × 5 = 2500

m = 2500/ 5 × 9.8

m = 5000/ 98

m = 51.02 kg

Hence, Mass of the person is 51.02 kg.