a person donates 20%of his savings to charitable trust . he distributes the rest among his two sons in ratio 1:2. if the total savings of person is 526500find the amount recieved by both the sons
Answers
Answer:
526500×80/100
=5265×80
=420800
The first son recieves ₹ 140400
The second son recieves ₹ 280800
Given data :
• Total recieved money is ₹ 526500
• The donated amount of money to the charity is 20%
• Distribution ratio among the two sons 1:2
- At first we have to calculate the donated amount of money.
= 526500 × 20/100
= ₹ 105300
- So the remaining amount of money
= (Total money - Donated money)
= (526500-105300)
= ₹ 421200
• Let,the distributed amounts of money among two sons = x and 2x (assume x as a variable to calculate the distributed amount of money among two sons)
• So, by comparing the calculated amount of total distributed money and the given amount of total distributed money,we get the following equation :
x+2x = 421200
3x = 421200
x = 421200/3
x = 140400
So,the first son gets = (1×140400) = ₹ 140400 (answer)
The second son gets = (2×140400) = ₹ 280800 (answer)