a person driving at 2/3 of his usual speed takes 2-3/4(two three by 4) hours extra to reach particular destination. Find the usual time taken by him.
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Answer:
5.5hrs
Step-by-step explanation:
speed= distance/time
speed is inversely proportional to time
let original speed be O, time be t1
let new speed be S, time t2
O:S = 1: 2/3
=3:2
t1:t2=2:3 (as speed inversely varies with time)
difference t2-t1 is 1 part =2 3/4hrs
t1 is 2 parts =2×2.75=5.5 hrs
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