A person facing north walks 3 km,
turns left and walks 4 km. Again, he
walks 3 km after turning right. Then,
he turns right and walks 12 km. What
is his displacement from the starting
point, and which direction is he
facing?
Answers
Answer:
10 km, east
Explanation:
Given : A person facing north walks 3 km, turns left and walks 4 km.
Again, he walks 3 km after turning right.
Then, he turns right and walks 12 km.
To Find :What is his displacement from the starting point, and which direction is he facing?
Solution:
NORTH
WEST EAST
SOUTH
Person walked 3 km towards North
NORTH = 3 km
took left turn and walk 4 km
Left turn from North is West
WEST = 4 km
a right turn and walk 3 km
Right turn from West means North
NORTH = 3 km
he turns right and walks 12 km.
Right turn from North is East
EAST = 12 km
Total NORTH = 3 + 3 = 6 km
Total EAST = 12 - 4 = 8 km ( 4 km WEST = - 4 km EAST)
NORTH & EAST are perpendicular to each other
Displacement = √8² + 6²
= √64 + 36
= √100
= 10
his displacement from the starting point = 10 km
Direction α = tan⁻¹( 6/8) ≈ 37°
Hence 37° toward North from East
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