Question

A person facing north walks 3 km, turns left and walks 4 km. Again, he walks 3 km after turning right. Then, he turns right and walks 12 km. What is his displacement from the starting point, and which direction is he facing? a. 10 km, east b. 12 km, east C. 10 km, northeast d. 12 km, north​

Answer 1

Answer:

He is walking North and 22km is his displacement.

Step-by-step explanation:

walks 3km north, then turns left for 4km which would be west then he turnns to the right for 12km which is North meaning if we add up al of the distances we get 22 and they are facing North.

Answer 2

Concept:

Displacement can be defined as the shortest distance between the two points.

Given:

A pathway of the person is given.

Find:

The displacement from the starting point and the direction.

Solution:

Let, the east direction be i, west be -i, north be j, and south be -j vectors for easier calculation.

Now, writing the paths using the taken direction,

x = 3j - 4i + 3j + 12i

Solving, x = 8i + 6j

The magnitude will be the displacement vector,

s = √(8²+6²) = √(64+36)

s = √100 = 10 km

The direction of the person is (i + j), this is the direction between north and east, i.e, northeast.

Hence, the displacement from the starting point is 10 km and he is facing in the north-east direction. Hence, the correct option is (c) 10 km, northeast.

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