Question

A person gave 1/5 partvof his income to his son and 40% part of his income to his daughter. He lent out the remaining money in three trusts A , B and C in ratio of 5:3:2 IF the difference between the amount got by son and daughter is rs.50,000 how much amount did he livest in trust B ?​

Answer 1

answer :

30 000

explanation :

let total income be 100%

he gave 20% to son

and 40% to daughter so the remaining 100-40-20 = 40% to a,b, c

also difference between amount between son and daughtee is 50000

so 40 -20 = 20% is 50 000

then 100 % will be 250 000

then 40 % will be 100 000

given ratio is a:b:c is 5:3:2 which is 40%

so 5x+3x+2x = 100 000

then x= 10000

so the ration of b is 3x= 3*10000

that is 30 000