Question

A person gets 3,000 if he sells either article. A at
10% profit and article B at 20% loss or article A at
10% loss and article B at 20% profit. The cost of A
is​

Answer 1

Answer:

Step-by-step explanation:  let, price of a=10x

                                                     price of b=10y

 Case1:- 10% prof., and 20%loss on a&b resp

             :10x pe 10% prof =11x

              10y pe 20% loss=8y

             11x+8y=3000   .........(1)

simillarly ,

  Case 2: 9x+12y=3000   .......(2)

solving 1&2 eqn x=200 and cp of A=2000

   

Answer 2

Given:

there is a profit of 3000 in both the cases:

• When A is sold at 10% profit and B is sold at 20% loss.

• When A is sold at 10% loss and B is sold at 20% profit.

To Find:

Cost of A.

Solution:

Framing the above conditions into equations:

$1.1A+0.8B=3000\\0.9A+1.2B=3000$

Solve the above equations by substitution method. We get:

$A=2000$

Hence the cost of A is 2000.