Math, asked by sona3393, 10 months ago

a person give one fifth part his income to his son and 40% part of his income to his daughter he lent out the remaining money in three trusts A B and C in the ratio of 5 is to 3 is to 2 if the difference between the amount got by son and daughter is rupees 50000 how much amount did he invest in trust b​

Answers

Answered by oshoraa
2

Answer:

Step-by-step explanation:

son= 1/5 of his income = 1/5 x income

daughter = 40% of his income = (40/100) x income

let the income = x

x/5 + 40 x/100 = 50000

(20 x / 100 )   + (40 x /100)  = 50000

60 x / 100   =  50000

X (income)  =  50000 x(100/60)

                   =  83333.33

money to trust

    =  83333.33 - 50000

   = 33333.33

A:B:C  = 5: 3: 2

so,trust B = (3/17) x 33333.33

                =  Rs. 5882.35


sona3393: but answer is rs 30000
Similar questions