A person gives two successive discount 0f x% on rs.720 and sells it at 259.20. Find the value of x?
Answers
Answer:
A person gives two successive discount 0f x% on rs.720 and sells it at 259.20. Find the value of x?
The discount x, is 20%
Step-by-step explanation:
Successive Discount is given by the following formula:
If the first discount is x% and 2nd discount is y% then ,
Total discount = ( x + y - xy / 100 ) %
In this case, both the first and second discount is x, therefore the formula will be:
( x + y - xy / 100 ) %
= ( x + x - x(x)/100)%
= (2x -x²)/100 %
This is the successive discount.
Therefore: (2x -x²)/100 % of 720 = 259.2
⇒ (2x -x²/100) × 1/100 × 720 = 259.2
⇒ 2x -x²/100 = 259.2 ×100/720
⇒ 2x - x²/100 = 36
⇒ 200x - x² = 3600
⇒ x² - 200x + 3600 = 0
Solve using product sum method:
x² - 200x + 3600 = 0
x² - 180x - 20x + 3600 = 0
x(x -180) - 20( x - 180) =
( x - 180) (x - 20) = 0
Therefore; x -180 = 0 or x - 20 = 0
Therefore x = 180 or 20
Therefore the discount is either 180% or 20%. If the discount was 180%, it would be a loss, therefore x = 20%
x = 20%
The other way of getting this successive discount is by going step-by-step and not using the formula:
x/100 × 720 = 7.2x
7.2 is the first discount
Subtract this from 720
720 - 7.2x
Get the next discount
x/100 (720 - 7.2x)
= 7.2x - 0.072x²
7.2x - 0.072x² is the second discount
Therefore: The sum of the two discounts should be equal to the total discount given
7.2x - 0.072x² + 7.2x = 259.2
14.4x - 0.072x² = 259.2
14400x - 72x² = 259200
72x² - 14400x + 259200 = 0
Solve using product sum method, just we did with the equation above:
x = 20%
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