Question

A person goes 4/5 of his usual speed reaches 10 min late to his destination,time taken?​

Answer 1

Given:-

•A person goes 4/5 of his usual speed reaches 10 min late to his destination.

To Find:-

•Time taken to complete total distance

Solution:-

Let consider speed be s and time be t in whole journey.

Using Formula:

$\: \: \sf \: speed = \frac{distance}{time}$

as we know in both cases distance is same

$\: \: \sf \: s1.t1 = s2.t2$

Now substitute the values,

$\: \: \sf \: s.t = ( \frac{4s}{5} ).(t + 10) \\ \\ \: \: \sf \: time = 40 min$

But we are said to find total time taken = 40 + 10 = 50 min

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Extra Info...

• Distance is defined as how much path he travelled.
• Speed is defined as the rate at which a body travel.
• Time is defined as how long somebody takes.