Question

a person goes from point P to point Q covering one third of the distance with speed 10 km per hour the next one third at 20 km per hour the next month the last one third at 60 km per hour what is the average distance​

Answer 1

Answer:

18 km/hr

Step-by-step explanation:

Let x=total time

 y = total distance

using T=D/R

Time for first 1/3 of distance = ( (y/3)/ 10 )

Time for second 1/3 of distance = ( (y/3)/20 )

Time for third 1/3 of distance = ( (y/3)/60 )

Time for entire trip = x = ( (y/3)/10 ) + ( (y/3)/20 ) + ( (y/3)/60 )

                          180x = 6y +3y + y

                           180x = 10y

                              x = y/18

 Rate for entire trip = D/T = y/x

                =  y / (y/18)

                =  y * (18/y)

                = 18 km/hr

Answer 2

Answer:

The average velocity​ of the entire trip is 18 km/hr.

Given:

A person goes from point P to point Q covering one third of the distance with speed 10 km per hour the next one third at 20 km per hour the next month the last one third at 60 km per hour  

Solution:

Speed = $\frac{Distance}{Time}$

Hence time = $\frac{Distance}{Speed}$

Time for $\frac{1}{3}$ distance = $\frac{\frac{d}{3}}{10}$

Time for next  $\frac{1}{3}$ distance = $\frac{\frac{d}{3}}{20}$

Next $\frac{1}{3}$ distance =$\frac{\frac{d}{3}}{60}$

Total time  = $\frac{\frac{d}{3}}{10}$ + $\frac{\frac{d}{3}}{20}$ + $\frac{\frac{d}{3}}{60}$

t = $\frac{d}{18}$

Rate for entire trip =  $\frac{\frac{d}{d}}{18}$ = 18 km/hr.

Result:

The average velocity​ of the entire trip is 18 km/hr.

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