A person goes from X to Y,separated by a distance 300 m and taking an about turn returns to Z.The distance between Y and Z is 100 m.If the time taken to go from X to Y is 200 s and Y to Z is100s,calculate the average. speed of the person: (a)For the journey between X and Y.
(b)For the journey between X and Z
Answers
Answered by
1
as the distance between X & Y is 300 m and the person travels it in 200 s. Speed = Distance/Time, Speed = 300/200 = 1.5 m/s
He returns to Z from Y, D=100s , t=100s, s=1 m/s
As average speed b/w X and Z is asked, we need to sum 1.5 + 1 and divide by 2
Answer a) 1.5m/s, b) 1.25m/s
He returns to Z from Y, D=100s , t=100s, s=1 m/s
As average speed b/w X and Z is asked, we need to sum 1.5 + 1 and divide by 2
Answer a) 1.5m/s, b) 1.25m/s
Similar questions