A person goes to certain distance at speed 4kmph. he returns on bicycle at the speed of 16kmph. find his average speed during the whole journey
Answers
Answered by
10
Let the distance be x km
so, time taken to go the distance with speed 4kmph
= x/4 hr
so, time taken to return with speed 16kmph
= x / 16 hr
so, total time = x/4 + x/16 = 5x/16 hr
total distance = x + x = 2x
so, average speed = 2x / (5x/16)
= 32/5 = 6.4 kmph
so, time taken to go the distance with speed 4kmph
= x/4 hr
so, time taken to return with speed 16kmph
= x / 16 hr
so, total time = x/4 + x/16 = 5x/16 hr
total distance = x + x = 2x
so, average speed = 2x / (5x/16)
= 32/5 = 6.4 kmph
Answered by
0
Let the distance be x km
so, time taken to go the distance with speed 4kmph
= x/4 hr
so, time taken to return with speed 16kmph
= x / 16 hr
so, total time = x/4 + x/16 = 5x/16 hr
total distance = x + x = 2x
so, average speed = 2x / (5x/16)
= 32/5 = 6.4 kmph
so, time taken to go the distance with speed 4kmph
= x/4 hr
so, time taken to return with speed 16kmph
= x / 16 hr
so, total time = x/4 + x/16 = 5x/16 hr
total distance = x + x = 2x
so, average speed = 2x / (5x/16)
= 32/5 = 6.4 kmph
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