A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed
by 20% as a result he reaches his office 16 minute late. What's the actual/original time he takes to reach
his office daily?
(1) 20 minutes
(2) 30 minutes
(3) 64 minutes
(4) 40 minutes
Answers
Answered by
0
Answer:
20 minutes
Explanation:
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Answered by
6
ANSWER
Let the speed by which he goes to his office be x.
So, his speed by 20%, his final speed would be
80%ofx
=10080x
= 54x
Initially:
Speed = td
x = d/t -----------(1)
xt = d
After decrease in speed
54x=td+16 -------(2)
Or the equation can also be written as -
4xt+64x=5d
Eliminating d from equation(1)&(2)
5xt=5d Rewriting Eq.1
4xt+64x=5d ---- Eq.2
4xt5xt+64x=1
5xt=4xt+64x
xt=64x
t=64 minutes
mark me brain list please
Let the speed by which he goes to his office be x.
So, his speed by 20%, his final speed would be
80%ofx
=10080x
= 54x
Initially:
Speed = td
x = d/t -----------(1)
xt = d
After decrease in speed
54x=td+16 -------(2)
Or the equation can also be written as -
4xt+64x=5d
Eliminating d from equation(1)&(2)
5xt=5d Rewriting Eq.1
4xt+64x=5d ---- Eq.2
4xt5xt+64x=1
5xt=4xt+64x
xt=64x
t=64 minutes
mark me brain list please
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