Physics, asked by tanishqkatiyar, 9 months ago

A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed
by 20% as a result he reaches his office 16 minute late. What's the actual/original time he takes to reach
his office daily?
(1) 20 minutes
(2) 30 minutes
(4) 40 minutes
(3) 64 minutes

Answers

Answered by Anonymous
5

A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed

by 20% as a result he reaches his office 16 minute late. What's the actual/original time he takes to reach

his office daily?

(3) 64 minutes✓✓✓✓✓

Answered by Anonymous
10

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A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed by 10% as a result he reaches his office 20 minute late. The actual time he takes to reach his office daily is:

December 26, 2019

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Mathi Krishnamoorthy

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ANSWER

Let the speed by which he goes to his office be x.

So, his speed by 20%, his final speed would be

80%ofx

=

100

80x

=

5

4x

Initially:

Speed =

t

d

x = d/t -----------(1)

xt = d

After decrease in speed

5

4x

=

t

d

+16 -------(2)

Or the equation can also be written as -

4xt+64x=5d

Eliminating d from equation(1)&(2)

5xt=5d Rewriting Eq.1

4xt+64x=5d ---- Eq.2

4xt

5xt

+64x=1

5xt=4xt+64x

xt=64x

t=64 minutes

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