Question

A person had a number of toys to distribute among children. At first he gave 2 toys to each child, then 3, then 4, then 5 and then 6 but was always left with 1. If he had given 7 toys to each child, no toys would have been left with him. What is the smallest number of toys that he had ?

Answer 1

Step-by-step explanation:

5C 2

ways to choose 2 toys as only 1 child can get max 2 toys.

There are 5−1=4 ways to choose the luckiest child, who will get 2 toys.

There are (5−2)!=3! ways to distribute the rest 3 toys to the remaining 3 children.

Hence, total no. of ways =5×4×3!×

5 C 2 =120×10=1200

Answer 2

Answer:

he gave to them children

Step-by-step explanation:

25toys he had