A person has a mass of 60 kg.If each of his foot has a surface area of 125 cm^2, the pressure exerted on his feet when he is standing is g =10m/s^2
Answers
Answer:
24,000 Pa
Explanation:
Given:
- Mass of a person (m) = 60 kg
- Surface area of each foot (A) = 125 cm² = 0.0125 m²
To find:
- Pressure when he is standing (P) = ?
Solution:
We remember,
Here, we have area i.e, 0.0125 m² we first need to find the force and then pressure.
Now, we also know that
Here, we are not given with the acceleration but acceleration due to gravity (g) so we'll use it. So, mg = Weight which is also a force.
F = 60 × 10
F = 600 N
Now, we have to find the pressure. We know the area of each foot i.e, 0.0125 m² so,
for 2 foots it will be 2 × 0.0125 = 0.025 m²
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* 1 Pascal = 1 Newton/metre² *
* 1000 Pa = 1 kPa or 1 kilopascal *
Pressure = 24,000Pascal
Force is a push or a pull acting on an object.
It is defined as the product of mass and acceleration of a body.
Pressure is the force applied on a unit area of an object. It is defined as the ratio of force applied to area.
Force is measured in Newton's.
Pressure is measured in pascals.
In this question we have been given mass of a person whose area of feet is given, we have to find the pressure on his feet.
In this question :-
- Area of one feet = 125cm^2 = 0.0125m^2
- Mass of person = 60kg
- Acceleration due to gravity = 10m/s^2
Now force on man = Its mass × Acceleration
Therefore force on person is 600N.
Now the pressure on person = Force / Area
Now in this case total area will be = 0.0125 × 2 , because humans have two feet.
Total surface area = 0.125 × 2 = 0.025m^2
Now the pressure on person :
Therefore the pressure on person is 24,000pascal.
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BY SCIVIBHANSHU
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