Math, asked by atzya, 5 hours ago

. A person has a sum of Rs 30, which is made up of rupee coins, 10 paise coins and 5 paise coins. There are dozen more 10 paise coins than rupee coins, and there are twice as many 5 paise coins. How many coins does he have in all? (1) 20 (2) 30 (3) 108 (4) 50
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Answers

Answered by kumarmanasvi
1

Step-by-step explanation:

Correct option is

B

54 of 10 p coins and 126 of 25 p coins

Given : Total no of coins =180

Let, the no of 10 paise coins x

No of 25 paise coins =180−x

Value of 10 paise coins =10x

Value of 25 paise coins =25(180−x)

A.T.Q,

10x+25(180−x)=3690

⟹10x+4500−25x=3690

⟹4500−3690=25x−10x

⟹15x=810

⟹x=

15

810

=54

∴ No of 10 paise coins =54

No of 25 paise coins =180−54=126

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Answered by prabsimar768
1

Answer:

x=3

Step-by-step explanation:

no. of rupee coins=6 ; no.of 5 pairs coins =12 ; no. of 10 pisa coins =18

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