Math, asked by sdfsfs9436, 1 year ago

A person has certain number of cows and birds.they have 172 eyes and 344 legs. how many cows and birds does he have?

Answers

Answered by Anonymous
3

Solutions :-


Given :


A person has certain number of cows and birds.


They have 172 eyes and 344 legs.


Now,


Let the number of birds be x


And the number of cows be y


So, The equation will be


2x + 2y = 172 ........... (i)  


(both have two eyes)


2x + 4y = 344........... (ii)


(birds have two legs and Cows have four legs)


Here,


Let us eliminate the y term, and in order to eliminate the y term, equate the coefficient of y in both the equation.


(2x + 2y = 172)2 => 4x + 4y = 344 ........... (iii)


(2x + 4y = 344)1 => 2x + 4y = 344 ........... (iv)


Subtract equation (iii) from (iv)


(2x + 4y) - (4x + 4y) = 344 - 344


=> -2x = 0


=> x = 0


Substitute the value of x in Eq. (i) or Eq. (ii) to find the value of y. Substitute the value of x in the first equation, we have,


2x + 2y = 172


=> 2(0) + 2y = 172


=> 0 + 2y = 172


=> y = 172/2 = 86


Number of birds = x = 0


Number of cows = y = 86


Hence,


He has only 86 cows and no any birds.

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