Question

a person has rs 960 in denomination rs 1 ,rs 5 ,rs 10 notes . the number of notes in each denomination is equal . what is the total number of notes​

Answer 1

Let the no. of 1 rupee coins, no. of five rupee notes and ten rupee notes be x each (as number of notes is equal in all three cases )... Amount of money in x one rupee notes is 1×X = X rupees... Amount of money in x five rupee notes is 5×X = 5X rupees... Amount of money in x ten rupee notes is 10×X = 10x rupees... Total amount (X+5X+10X) is 480... This implies that 16X = 480.. This gives X= 30.. Total number of notes that he has is 30+30+30(1,5,10 rupee notes) = 90 notes...

Answer 2

Given,

The total amount the man has is Rs $\[960.\]$

Solution,

Assume that the man has x number of notes of $\[{\rm{Rs}}1,{\rm{Rs}}5\,{\rm{and Rs}}10\]$ respectively.

So,

$\[\begin{array}{l} \Rightarrow \left( {1 \times x} \right) + \left( {5 \times x} \right) + \left( {10 \times x} \right) = 960\\ \Rightarrow x + 5x + 10x = 960\\ \Rightarrow 16x = 960\end{array}\]$

Solve further,

$\[\begin{array}{l} \Rightarrow x = \frac{{960}}{{16}}\\ \Rightarrow x = 60\end{array}\]$

Therefore, the total number of notes

$\[\begin{array}{l} \Rightarrow 60 + 60 + 60\\ \Rightarrow 180\end{array}\]$

Hence, the total number of notes are $\[180.\]$