Math, asked by sk0567752, 3 months ago

A person has three iron bars whose lengths are 10,15,20 meters respectively. He wants to cut pieces of same length from each of the three bars. What is the least number of total pieces if he is cut without any wastage

Answers

Answered by muskan845587

1

Answer:

9

Step-by-step explanation:

HCF of 10,15 and 20 = 5

From 10m long iron bar he cuts 2 pieces

From 15m long iron bar he cuts 3 pieces

From 20m long iron bar he cuts 4 pieces

Toatal= 9 pieces

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