a person has three varieties of rice. the first variety weighs 117kg, the second variety weighs 130kg and the third variety weighs 143kg. find the least number of bags of equal size, which are required to store the different varieties without mixing them.
Answers
Answer:
take the average so that you will get the least value which is 130 bags of equal size
The least number of bags of equal size, which are required to store the different varieties without mixing them are 30 bags of 13kg each.
Given:
Variety 1 = 117kg
Variety 2 = 130kg
Variety 3 = 143kg
To find:
Least number of bags needed of equal size.
Solution:
Since, we are supposed to find the least number of bags of equal size, which are required to store the different varieties without mixing them, we need to take GCD or HCF of all three weights.
Concept used:
GCD - Greatest Common Divisor
HCF - Highest Common Factor
GCD or HCF is the largest number or quantity which divides the numbers.
117 = 3 × 3 × 13
130 = 2 × 5 × 13
143 = 11 × 13
As, we can see above only 13 is the common factors in all quantities, it is the GCD or HCF.
As, we have to find number bags we need to divide total weight by GCD or HCF.
Total weight = 117 + 130 + 143 = 390.
390 ÷ 13 = 30
Therefore, the least number of bags of equal size, which are required to store the different varieties without mixing them are 30 bags of 13kg each.