Question

A person has three varieties of rice. The first variety weighs 117kg, the second variety
weighs 130kg and the third variety weighs 143 kg. Find the least number of bags of equal
size, which are required to store the different varieties without mixing them.
PLEASE GIVE ANSWER STEP BY STEP WITH PROPER EXPLANATION

Answer 1

We need 30 bags of 13 kg each.

Step-by-step explanation:

Step 1 of 4

First of all we need to find out the HCF of all the numbers. So, for that break the terms into their prime number

177 =3 × 3 × 13

130 = 2 × 5 × 13

143 = 11 × 13

Step 2 of 4

The next step is to find the common factor in the prime number which is 13.

Step 3 of 4

Now we need to find out the total number of bags. For that

117 + 130 + 143 = 390 is the total weight

Step 4 of 4

Divide 390 by 13, we get

390/13 = 30

Hence we need 30 bags of 13 kg each.