Question

a person has to cover a certain distance he cover 2/5th of the total distance by car, 3/10th by the bus and 1/5th by the auto rickshaw and remaining 5 kilometers on foot what is the total distance

Answer 1

• Let total distance be "M".

》 A person covers 2/5th of the total distance by car, 3/10th by the bus and 1/5th by the auto rickshaw.

=> $\dfrac{2}{5}$ of the total distance + $\dfrac{3}{10}$ of the total distance + $\dfrac{1}{5}$ of the total distance.

=> $\dfrac{2M}{5}$ + $\dfrac{3M}{10}$ + $\dfrac{1M}{5}$

=> $\dfrac{4M\:+\:3M\:+\:2M}{10}$

=> $\dfrac{9M}{10}$

》 The remaining journey of man is 5 km on foots.

=> Total journey - Remaining journey

=> M - 5

According to question,

=> M - 5 = $\dfrac{9M}{10}$

Cross multiply them

=> 10(M - 5) = 9M

=> 10M - 50 = 9M

=> 10M - 9M = 50

=> M = 50

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Total distance = 50 km

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☆ VERIFICATION :

From above calculations we have = 50

Put value of M in this : M - 5 = $\dfrac{9M}{10}$

=> 50 - 5 = $\dfrac{9(50)}{10}$

=> 45 = $\dfrac{450}{10}$

=> 45 = 45

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