A person has to reach a place in a certain time and he find that he will be 15minutes late, if he walks at 4km/h and 10 minutes earlier if he walks at 6km/h. find the distance he has to cover?
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d=vt
d=4(t+0.25)=6(t-1/6)
4t+1=6t-1
t=1hr
d=4(1.25)=5km
d=4(t+0.25)=6(t-1/6)
4t+1=6t-1
t=1hr
d=4(1.25)=5km
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