A person has to walk 100m to go from position X in the north of East direction to the position B and then to the west of Y to reach finally at the position Z. the position Z is situated at the north of X and at a distance of 60m from X. find the distance between X and Y.
Answers
Given :- A person has to walk 100m to go from position X in the north of East direction to the position Y and then to the west of Y to reach finally at the position Z. the position Z is situated at the north of X and at a distance of 60m from X. find the distance between Z and Y. ?
Solution :-
from image we have ,
→ ZX = 60 m .
→ XY = 100 m .
→ ∠XZY = 90°
So, in right angle ∆XZY,
→ ZY² + ZX² = XY² (By pythagoras theorem.)
→ ZY² + 60² = 100²
→ ZY² = 100² - 60²
→ ZY² = 10000 - 3600
→ ZY² = 6400
→ ZY² = (80)²
→ ZY = 80 m . (Ans.)
Hence, the distance between Z and Y is 80 m.
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