Question

A person having initial velocity 5m/sec moves with a constant acceleration 2m/sec^2. for a time 10sec along a straight line. find the displacement of the particle in last one second.​

Answer 1

Answer:

24m

Explanation:

u=5ms^-1

a=2ms^-2

t=n=10s

WKT,

Sn=u+a(n-1/2)

S10=5+2(10-1/2)

S10=5+2(19/2)

S10=5+19

S10=24m