Question

A person hold on a weight of 10 kg at a height of 5m above the ground for 5 min. Work done by him is


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Answer 1

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Here , Force = Mass × Acceleration

$= mass \: \times (\frac{v \: - \: u}{t} )$

$= 10 \: \times \frac{(0 \: - \: 0)}{(5 \times 60 \: seconds} )$

• Here , V = 0 ( Because the body was stationary )

• Here , V = 0 ( Because the body was stationary )Also , U = 0 ( Because the body was stationary )

$= 10 \: \times \: (\frac{0}{300} )$

$= 0 \: ( \: zero \: )$

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Now , We know that / —

Now , We know that / — Work Done = Force × Distance

• Now , We know that / — Work Done = Force × Distance = 0 × 5 m
• Now , We know that / — Work Done = Force × Distance = 0 × 5 m = 0 ( Zero ) Joules

Joules Hence , work done by him is 0 ( Zero ) Joules .

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