Question

A person holding a rifle (mass of person and rifle together is 100 kg ) stands on a smooth surface and fires 10 shots horizontally in 5 s. Each bullet has a mass of 10 g with a muzzle velocity of 800 m/s . The final velocity acquired by the person and the average force exerted on the person are

Answer 1

Answer:

Step-by-step explanation:

By the law of momentum conservation:-

=>P(iniitial) = P(final)

=>mu1 + Mu2 = mv1 +Mv2

=>0 + 0 = nmu + (M-nm)v

=>10 x 10 x 10^-3 x 800 + (100 - 10 x 10 x 10^-3) x v

=>v = -0.80 m/s {-ve just indicating the direction is opposite to the direction of bullets}

By F = ∆P/∆t

=>F = {10 x 10 x 10^-3 x 800}/5 = 16N