Question

A person holds a block weighing 2 kg between his hands and keeps it from falling down by pressing itwith his hands. If the force exerted by each hand horizontally is 50 N, the coefficient of friction betweenthe hand and the block is (g = 10 ms -2)cala) 0.2b) 0.4c) 0.1d) 0.5​

Answer 1

Answer:

Option (a) 0.2

Explanation:

The weight of the block will act downwards while the normal rection from pressing the block with both the hands will act horizontally. The ball remains in rest because of the frictional force between the hands and the block

Let the coefficient of friction is μ

Force exerted by each hand = 50 N

Frictional force on each hand = 50 × μ

Frictional force on both hands = 2 × 50 × μ = 100μ

This force will be equal to the weight of the block

Thus,

100μ = 2g

100μ = 2 × 10

or, μ = 20/100 = 0.2

Hope this helps

Answer 2

Answer:

option (a) 0.2

Explanation:

is the correct answer ☺️.........