Question

A person holds a bucket of wA person holds a bucket of weight 60N. He walks 10m along the horizontal and climb up a vertical distance of 5m. How much work done by the man ?

Answer 1

here we will only count the work done by the person when he is moving vertical distance because when he is moving in horizontal distance his displacement is towards horizontal side and the force of bucket is towards vertical since the angle between force and displacement is 90 degree therefore its work done will be equals to zero and now for the work done from vertical distance covered will be
displacement= 5m
and force = 60 N
therefore work done = force × displacement
= 5×60 =300 joules
and the total work done will be also equals to 300 Joule

Answer 2

125 x 60
As 5sq + 10sq is 125 and when right angled ∆ is formed then the displacement is the hypotenuese ... so WD IS FORCE INTO DISP
I.E. 125x60 is 7500 joules