Question

) A person hurls a stone vertically up in the air with an initial velocity of 50 m.s? (Take g = 10 m.s)
i. What is the maximum height achieved by the stone?

ii. How much time does the stone take to return to the ground?

iii. Determine the average speed of the stone.
​

Answer 1

Answer:

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s