Question

A person in an elevator accelerating up- wards with an acceleration of 2 m s?, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand ? (Take g = 10 ms^2)
1. 5/3 s
2. 3/10 s
3. 10/3 s
4. 3/5 s

please give full information​

Answer 1

Answer :

Acceleration of the elevator = 12 m/s^2

Then, initial velocity of coin (u) = 20ms-1

So, by using the formula...

S=ut+1/2at^2

time = 10/3 sec.

So, option 3rd is correct

Thank you