Question

a person in an elevator accelerating upwards with an acceleration of 2 ms^-2, tosses a coin vertically upwards with a speed of 20 m/s. after how much time will the coin fall back into his hand

Answer 1

as it is a non-inertial frame the net acceleration of the  particle will be 10 + 2 m/s2 (taking g=10)

when it will fall back into his hands the displacement of the particle will be zero with respect to the man

 so 
using formula 
s=ut+1/2 at^2
0=20t-1/2 x 12 x t^2
we neglect t=0
20-6t=0
t= 20/6
t=10/3 sec



 please vote brainliest

Answer 2

t=10/3s time will the coin fall back into his hand