Math, asked by islamshah93, 1 day ago

a person insured his vehicle worth Rs 450,000 at a rate of 2.5% for 4 years. After 3 years he got a claim of damages worth Rs 750,000.how much loss had he recovered through insurance. answer by step by step explanation​

Answers

Answered by shahrukh972
2

Answer:

Loss Recovered =  Rs. 719512.5

Step-by-step explanation:

Car / Vehicle amount = Rs. 450,000

1st premium = rate of premium * total amount of the vehicle / 100

1st premium = 2.5 * 450000 / 100

1st premium = Rs. 11250

Depreciation = 10% of the total amount of the vehicle

Depreciation = 10 * 450000 / 100

Depreciation = 45000

Depreciation Price = total amount of the vehicle - Depreciation

Depreciation Price = 450000 - 45000

Depreciation Price = 405000

2nd Premium = rate of premium * Depreciation Price after 1st premium  / 100

2nd Premium = 2.5 * 405000 / 100

2nd Premium = Rs. 10125

Depreciation = 10% of the total amount of the vehicle

Depreciation = 10 * 405000 / 100

Depreciation = 40500

Depreciation Price = the total amount of the vehicle - Depreciation

Depreciation Price = 405000 - 40500

Depreciation Price = 364500

3rd premium = rate of premium * Depreciation Price after 2nd premium  / 100

3rd premium = 2.5 * 364500 / 100

3rd premium = Rs. 9112.5

4th Premium = 0

The Total amount paid as insurance = 1st premium + 2nd premium + 3rd premium + 4th premium

The Total amount paid as insurance = 11250 + 10125 + 9112.5 + 0

The Total amount paid as insurance = Rs. 30487.5

He Claimed = Rs. 750,000

Loss Recovered = Total Claimed - Total amount paid as insurance

Loss Recovered = 750000 - 30487.5

Loss Recovered =  Rs. 719512.5

Answered by ubaidgoodboy6
0

Answer:

Data:

value of property =450,000

rate of premium =2.5℅

tenure =4 years

claim worth = 750,000

Required:

Loss covered =??

1st premium =2.5℅ × 450,000

= 2.5/ 100 × 450,000

= 25/ 1000 × 450,000

=25×450

= 11250

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