Math, asked by novakbishnushaw, 9 months ago

A person invests ₹10000 for two years at a certain rate of interest, compounded annually. At the end of one year this sum amounts to ₹11200. Calculate:-
i) The rate of interest.
ii) The amount at the end of second year.

Answers

Answered by FehlingSolution

Please refer to the attachment.

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Answered by PraptiMishra05

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Here, P = 10000

A = 112200

T = 1

So, A = P (1 + $\frac{R}{100}$

$\frac{112200}{10000}$ = P (1 + $\frac{R}{100)}$

1 + $\frac{12}{100}$ = 1 + $\frac{R}{100}$

So, R = 12 percent

Now after two years,

A = P (1 + $\frac{12²}{100})$ = 10000 × $\frac{28}{25}$ × $\frac{28}{25}$

= 16 × 28 × 28

= Rs. 12544

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