A person invests 7 5000 for two years at a certain rate of interest compounded annually. At the end of one year, this sum amounts to 2 5600. Calculate (i) the rate of interest per year (ii) the amount at the end of the second year.
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Solution :-
Simple Interest I= PNR/100
Here for first year,
P= Rs. 5,000
N=1 year
N=1 year
So, Interest at the end of 1st year I=A−P=5,600−5,000= Rs. 600
⇒600=5000×1×R/100
⇒R=12%
So, Interest at the end of 2nd year =
5600×1×12/100=Rs.672
And Amount at the end of 2nd year = Rs. 5,600+ Rs. 672= Rs. 6,272
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