A person invests ₹ 8,400 at 14% p.a. compound interest for 2 years. [5]
Calculate :
(i) the interest for the 1st year,
(ii) the amount at the end of the 1st year.
(iii) the interest for the second year, correct to the nearest rupee.
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A man invests Rs. 5,600 at 14% per annum compound interest for 2 years. Calculate the interest for the second year, correct to the nearest rupee.
ANSWER
For the first year:
P= Rs. 5,600, N=1 year and R=14%
We have S.I. =
100
PNR
=
100
5,600×1×14
= Rs. 784
And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384
Now, for the second year :
P= Rs. 6,384, N=1 year and R=14%
We have S.I.=
100
PNR
=
100
6,384×1×14
= Rs. 893.76
To the nearest rupee, it is Rs. 894.
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