Question

A person invests money in three different schemes for 6 years,10 years and 12 years at 10%, 12% and 15% simple interest respectively.At the completion of each scheme he gets the same interest. The ratio of his investment is ?​

Answer 1

Answer:

6:3:2

Step-by-step explanation:

take principals in each scheme be x,y,z rate of interests in each scheme=10,12,15 time periods =6years,10years,12years find interest for each scheme then you will get relation between x,y,z write x,y,z in the form of y then find x: y:z that is the ratio of his investment

Answer 2

Answer:

$\huge\underline\bold {Answer:}$

Let the required ratio be x : y : z. Then,

S.I. on x rupees for 6 years at 10% p.a. = S.I. on y rupees for 10 years at 12% p.a.

$= > \frac{x \times 6 \times 10}{100} = \frac{y \times 10 \times 12}{100}$

$= > \frac{x}{y} = \frac{2}{1}$

S.I. on y rupees for 10 years at 12% p.a. = S.I. on z rupees for 12 years at 15% p.a.

$= > \frac{y \times 10 \times 12}{100} = \frac{z \times 12 \times 15}{100} \\ = > \frac{y}{z} = \frac{3}{2}$

x : y = 2 : 1 and y : z = 3 : 2

=> x : y = 6 : 3 and y : z = 3 : 2

=> x : y : z = 6 : 3 : 2

Therefore the ratio of his investments is 6 : 3 : 2.